Summarize Timeline Top Qs Fact Check
Eine Mehrfachpotenzreihe
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{\displaystyle \sum _{k_{1}\geq 0}\cdots \sum _{k_{n}\geq 0}a_{k_{1},\ldots ,k_{n}}(z_{1}-z_{1}^{o})^{k_{1}}\cdots (z_{n}-z_{n}^{o})^{k_{n}}}
lässt sich kurz schreiben als
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a
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{\displaystyle \sum _{{\boldsymbol {k}}\geq 0}a_{\boldsymbol {k}}({\boldsymbol {z}}-{\boldsymbol {z}}^{o})^{\boldsymbol {k}}}
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Leibniz-Regel
Ist
m
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{\displaystyle {\boldsymbol {m}}\in \mathbb {N} ^{n}}
und sind
f
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{\displaystyle f,g\colon \mathbb {R} ^{n}\to \mathbb {R} }
m-mal stetig differenzierbare Funktionen, so gilt
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f
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{\displaystyle (fg)^{({\boldsymbol {m}})}=\sum _{{\boldsymbol {k}}\leq {\boldsymbol {m}}}{{\boldsymbol {m}} \choose {\boldsymbol {k}}}f^{({\boldsymbol {k}})}g^{({\boldsymbol {m}}-{\boldsymbol {k}})}}
beziehungsweise
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{\displaystyle {\frac {(fg)^{({\boldsymbol {m}})}}{{\boldsymbol {m}}!}}=\sum _{{\boldsymbol {k}}+{\boldsymbol {j}}={\boldsymbol {m}}}{\frac {f^{({\boldsymbol {k}})}}{{\boldsymbol {k}}!}}{\frac {g^{({\boldsymbol {j}})}}{{\boldsymbol {j}}!}}}
.
Diese Identität heißt Leibniz-Regel .
Und sind
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{\displaystyle f_{1},\ldots ,f_{n}\colon \mathbb {R} \to \mathbb {R} }
m-mal stetig differenzierbare Funktionen, so ist
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m
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{\displaystyle {\frac {(f_{1}\cdots f_{n})^{m}}{m!}}=\sum _{|{\boldsymbol {k}}|=m}{\frac {{\boldsymbol {f}}^{({\boldsymbol {k}})}}{{\boldsymbol {k}}!}}}
,
wobei
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{\displaystyle {\boldsymbol {f}}^{({\boldsymbol {k}})}=(f_{1},\ldots ,f_{n})^{{\big (}(k_{1}),\ldots ,(k_{n}){\big )}}=f_{1}^{(k_{1})}\cdots f_{n}^{(k_{n})}}
ist.
Für Mehrfachpotenzreihen
f
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{\displaystyle f({\boldsymbol {z}})=\sum _{|{\boldsymbol {\ell }}|\geq 0}a_{\boldsymbol {\ell }}\,{\boldsymbol {z}}^{\boldsymbol {\ell }}\;,\;g({\boldsymbol {z}})=\sum _{|{\boldsymbol {\ell }}|\geq 0}b_{\boldsymbol {\ell }}\,{\boldsymbol {z}}^{\boldsymbol {\ell }}}
gilt
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{\displaystyle f({\boldsymbol {z}})\,g({\boldsymbol {z}})=\sum _{|{\boldsymbol {\ell }}|\geq 0}\left(\sum _{{\boldsymbol {k}}+{\boldsymbol {j}}={\boldsymbol {\ell }}}a_{\boldsymbol {k}}\,b_{\boldsymbol {j}}\right){\boldsymbol {z}}^{\boldsymbol {\ell }}}
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Sind
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{\displaystyle f_{1}(z)=\sum _{\ell =0}^{\infty }a_{1\ell }z^{\ell }\;,\;\ldots \;,\;f_{n}(z)=\sum _{\ell =0}^{\infty }a_{n\ell }z^{\ell }}
Potenzreihen einer Veränderlichen, so gilt
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{\displaystyle f_{1}(z)\cdots f_{n}(z)=\sum _{\ell =0}^{\infty }\left(\sum _{|{\boldsymbol {k}}|=\ell }a_{\boldsymbol {k}}\right)z^{\ell }}
, wobei
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{\displaystyle a_{\boldsymbol {k}}=a_{1k_{1}}\cdots a_{nk_{n}}}
ist.
Für
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{\displaystyle {\boldsymbol {z}}=(z_{1},...,z_{n})\in \mathbb {C} ^{n}}
gilt
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{\displaystyle e^{z_{1}+...+z_{n}}=\sum _{{\boldsymbol {k}}\in \mathbb {N} _{0}^{n}}{\frac {{\boldsymbol {z}}^{\boldsymbol {k}}}{{\boldsymbol {k}}!}}}
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In mehreren Veränderlichen
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{\displaystyle z_{1},\ldots ,z_{n}\,}
lässt sich die cauchysche Integralformel
D
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{\displaystyle {\frac {D^{\boldsymbol {k}}f(z_{1},\ldots ,z_{n})}{{\boldsymbol {k}}!}}={\frac {1}{(2\pi i)^{n}}}\oint _{\partial U_{n}}\cdots \oint _{\partial U_{1}}{\frac {f(\xi _{1},\ldots ,\xi _{n})}{(\xi _{1}-z_{1})^{k_{1}+1}\cdots (\xi _{n}-z_{n})^{k_{n}+1}}}d\xi _{1}\cdots d\xi _{n}}
kurz schreiben als
a
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D
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{\displaystyle a_{\boldsymbol {k}}:={\frac {D^{\boldsymbol {k}}f({\boldsymbol {z}})}{{\boldsymbol {k}}!}}={\frac {1}{(2\pi i)^{\boldsymbol {1}}}}\oint _{\partial {\boldsymbol {U}}}{\frac {f({\boldsymbol {\xi }})}{({\boldsymbol {\xi }}-{\boldsymbol {z}})^{{\boldsymbol {k}}+{\boldsymbol {1}}}}}\,{\boldsymbol {d\xi }}}
,
wobei
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{\displaystyle \partial {\boldsymbol {U}}=\partial U_{1}\times \cdots \times \partial U_{n}}
sein soll. Ebenso gilt die Abschätzung
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{\displaystyle |a_{\boldsymbol {k}}|\leq {\tfrac {M}{{\boldsymbol {r}}^{\boldsymbol {k}}}}}
, wobei
M
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max
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{\displaystyle \textstyle M=\max _{{\boldsymbol {\xi }}\in \partial {\boldsymbol {U}}}|f({\boldsymbol {k}})|}
ist.
Hurwitz-Identität
Für
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{\displaystyle x,y\in \mathbb {C} }
mit
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{\displaystyle x\neq 0}
und
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∈
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{\displaystyle {\boldsymbol {a}}=(a_{1},...,a_{n})\in \mathbb {C} ^{n}}
gilt
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{\displaystyle (x+y)^{n}=\sum _{{\boldsymbol {0}}\leq {\boldsymbol {k}}\leq {\boldsymbol {1}}}x\,(x+{\boldsymbol {a}}\cdot {\boldsymbol {k}})^{|{\boldsymbol {k}}|-1}\,(y-{\boldsymbol {a}}\cdot {\boldsymbol {k}})^{n-|{\boldsymbol {k}}|}}
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Dies verallgemeinert die Abelsche Identität
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{\displaystyle (x+y)^{n}=\sum _{k=0}^{n}{n \choose k}\,x\,(x+ak)^{k-1}\,(y-ak)^{n-k}}
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Letztere erhält man im Fall
a
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{\displaystyle {\boldsymbol {a}}=(a,a,...,a)}
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