1905 Paris–Roubaix
Cycling race
From Wikipedia, the free encyclopedia
The 1905 Paris–Roubaix was the tenth edition of the Paris–Roubaix, a classic one-day cycle race in France. The single day event was held on 23 April 1905 and stretched 268 km (167 mi) from Paris to its end in a velodrome in Roubaix.[1] The winner was Louis Trousselier from France.[2]
Dates23 April 1905
Stages1
Distance268 km (167 mi)
Winning time8h 4' 15"
| Race details | ||||||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Dates | 23 April 1905 | |||||||||
| Stages | 1 | |||||||||
| Distance | 268 km (167 mi) | |||||||||
| Winning time | 8h 4' 15" | |||||||||
| Results | ||||||||||
| ||||||||||
Results
| Rank | Cyclist | Time |
|---|---|---|
| 1 |  Louis Trousselier (FRA) |
8h 4' 15″ |
| 2 | René Pottier (FRA) |
+7' 00″ |
| 3 | Henri Cornet (FRA) |
+16' 00″ |
| 4 | Hippolyte Aucouturier (FRA) |
+23' 00″ |
| 5 | Edouard Wattelier (FRA) |
+48' 00″ |
| 6 | Claude Chapperon (FRA) |
+57' 00″ |
| 7 |  Alois Catteau (BEL) |
+1hr 6' 00″ |
| 8 | Paul Chauvet (FRA) |
+1hr 12' 00″ |
| 9 | Lazare Brault (FRA) |
+1hr 20' 00″ |
| 10 | Louis Coolsaet (FRA) |
+1hr 20' 01″ |
