1948 U.S. National Championships – Women's singles
1948 tennis event results
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Third-seeded Margaret Osborne duPont defeated Louise Brough 4–6, 6–4, 15–13 in the final to win the women's singles tennis title at the 1948 U.S. National Championships.[1][2]
| Women's singles | |
|---|---|
| 1948 U.S. National Championships | |
| Champion |  Margaret Osborne duPont[1] |
| Runner-up | Louise Brough |
| Score | 4–6, 6–4, 15–13 |
Seeds
The seven seeded U.S. players are listed below. Margaret Osborne duPont is the champion; others show in brackets the round in which they were eliminated.[3]
Louise Brough (finalist)- Doris Hart (quarterfinals)
- Margaret Osborne duPont (champion)
- Pat Canning Todd (semifinals)
- Shirley Fry (third round)
- Beverly Baker (quarterfinals)
- Gussy Moran (semifinals)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- r = Retired
Final eight
| Quarterfinals | Semifinals | Finals | ||||||||||||||||||
| 7 | Gussy Moran
| 6 | 6 | |||||||||||||||||
| 2 | Doris Hart
| 4 | 4 | |||||||||||||||||
| 7 | Gussy Moran
| 8 | 4 | |||||||||||||||||
| 3 | Margaret Osborne duPont
| 10 | 6 | |||||||||||||||||
| 3 | Margaret Osborne duPont
| 1 | 6 | 6 | ||||||||||||||||
| Beverly Baker
| 6 | 2 | 0 | |||||||||||||||||
| 3 | Margaret Osborne duPont
| 4 | 6 | 15 | ||||||||||||||||
| 1 | Louise Brough
| 6 | 4 | 13 | ||||||||||||||||
| 1 | Louise Brough
| 6 | 6 | |||||||||||||||||
| Virginia Kovacs
| 3 | 2 | ||||||||||||||||||
| 1 | Louise Brough
| 6 | 6 | |||||||||||||||||
| 4 | Pat Canning Todd
| 3 | 3 | |||||||||||||||||
| 4 | Pat Canning Todd
| 6 | 6 | |||||||||||||||||
| Madge Vosters
| 3 | 1 | ||||||||||||||||||