1953 U.S. National Championships – Women's singles

1953 tennis event results From Wikipedia, the free encyclopedia

Two-time defending champion Maureen Connolly defeated Doris Hart in the final, 6–2, 6–4 to win the women's singles tennis title at the 1953 U.S. National Championships. With the win, she became the first woman in history to complete the Grand Slam.[1] Connolly won the tournament without losing a set.[2]

Runner-upUnited States Doris Hart
Score6–2, 6–4
Seeds8
Quick facts Women's singles, Final ...
Women's singles
1953 U.S. National Championships
Final
ChampionUnited States Maureen Connolly[1]
Runner-upUnited States Doris Hart
Score6–2, 6–4
Details
Seeds8
Events
Singles men women
Doubles men women
Close

Seeds

The seeded players are listed below. Maureen Connolly is the champion; others show in brackets the round in which they were eliminated.[3]

  1. United States Maureen Connolly (champion)
  2. United States Doris Hart (finalist)
  3. United States Shirley Fry (semifinals)
  4. United States Louise Brough (semifinals)
  5. United States Margaret Osborne duPont (quarterfinals)
  6. United States Althea Gibson (quarterfinals)
  7. United States Helen Perez (quarterfinals)
  8. United States Babara Lewis (third round)

Draw

Key

Final eight

Quarterfinals Semifinals Finals
               
1 United States Maureen Connolly 6 6
6 United States Althea Gibson 3 2
1 United States Maureen Connolly 6 6
3 United States Shirley Fry 1 1
5 United States Margaret Osborne duPont 6 5
3 United States Shirley Fry 8 7
1 United States Maureen Connolly 6 6
2 United States Doris Hart 2 4
7 United States Helen Perez 6 3
4 United States Louise Brough 8 6
4 United States Louise Brough 2 4
2 United States Doris Hart 6 6
United Kingdom Jean Rinkel-Quertier 0 1
2 United States Doris Hart 6 6

References

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