Lemoine hexagon

The Lemoine hexagon can be drawn defined in two ways, first as a simple hexagon with vertices at the intersections as defined before. The second is a self-intersecting hexagon with the lines going through the symmedian point as three of the edges and the other three edges join pairs of adjacent vertices.

For the simple hexagon drawn in a triangle with side lengths ${\displaystyle a,b,c}$ and area ${\displaystyle \Delta }$ the perimeter is given by

${\displaystyle p={\frac {a^{3}+b^{3}+c^{3}+3abc}{a^{2}+b^{2}+c^{2}}}}$

and the area by

${\displaystyle K={\frac {a^{4}+b^{4}+c^{4}+a^{2}b^{2}+b^{2}c^{2}+c^{2}a^{2}}{\left(a^{2}+b^{2}+c^{2}\right)^{2}}}\Delta }$

For the self intersecting hexagon the perimeter is given by

${\displaystyle p={\frac {\left(a+b+c\right)\left(ab+bc+ca\right)}{a^{2}+b^{2}+c^{2}}}}$

and the area by

${\displaystyle K={\frac {a^{2}b^{2}+b^{2}c^{2}+c^{2}a^{2}}{\left(a^{2}+b^{2}+c^{2}\right)^{2}}}\Delta }$