Samarium(II) chloride
Chemical compound
From Wikipedia, the free encyclopedia
Samarium(II) chloride (SmCl2) is a chemical compound, used as a radical generating agent in the ketone-mediated intraannulation reaction.
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| Names | |
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| IUPAC name
Samarium(I) chloride | |
| Other names
Samarium dichloride | |
| Identifiers | |
3D model (JSmol) |
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| ChemSpider | |
| ECHA InfoCard | 100.034.196 |
| EC Number |
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PubChem CID |
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CompTox Dashboard (EPA) |
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| Properties | |
| SmCl2 | |
| Molar mass | 221.27 g/mol |
| Appearance | dark brown crystals[1] |
| Density | 3.69 g/cm3, solid |
| Melting point | 855 °C (1,571 °F; 1,128 K) |
| Boiling point | 1,310 °C (2,390 °F; 1,580 K) |
| ? | |
| Structure | |
| Orthorhombic | |
| Pbnm, No. 62[2] | |
| Related compounds | |
Other anions |
Samarium(II) bromide Samarium(II) iodide |
Other cations |
Samarium(III) chloride |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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Preparation
Reduction of samarium(III) chloride with samarium metal in a vacuum at a temperature of 800 °C to 900 °C, or with hydrogen gas at 350 °C yields samarium(II) chloride:[1]
- 2 SmCl3 + Sm → 3 SmCl2
- 2 SmCl3 + H2 → 2 SmCl2 + 2 HCl
Samarium(II) chloride can also be prepared by reducing samarium(III) chloride with lithium metal/naphthalene in THF:[3]
- SmCl3 + Li → SmCl2 + LiCl
A similar reaction has been observed with sodium.[2]
Structure
Physical properties
The compound co-crystallises with fermium dichloride (FmCl2).[4]
