Samarium(III) bromide
Chemical compound
From Wikipedia, the free encyclopedia
Samarium(III) bromide is a crystalline compound of one samarium and three bromine atoms with the chemical formula of SmBr3. The compound has a crystal structure isotypic to that of plutonium(III) bromide.[4][5]
| Names | |
|---|---|
| IUPAC name
Samarium(III) bromide | |
| Other names
Samarium tribromide Tribromosamarium | |
| Identifiers | |
3D model (JSmol) |
|
| ChemSpider | |
| ECHA InfoCard | 100.033.938 |
| EC Number |
|
PubChem CID |
|
CompTox Dashboard (EPA) |
|
| |
| |
| Properties | |
| SmBr3 | |
| Molar mass | 390.07 g·mol−1 |
| Appearance | Light yellow solid[1][2] |
| Melting point | 700 °C (1,292 °F; 973 K)<[3] |
| +972.0·10−6 cm3/mol | |
| Hazards | |
| GHS labelling: | |
| Warning | |
| H315, H319, H335[3] | |
| P261, P305+P351+P338[3] | |
| Related compounds | |
Other anions |
Samarium(III) fluoride Samarium(III) chloride |
Other cations |
Samarium(II) bromide |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
| |
Preparation
SmBr3·6H2O can be crystallized by dissolving samarium oxide in 40% hydrobromic acid. The hydrate and ammonium bromide are heated in a vacuum to obtain the anhydrous form of samarium(III) bromide.[2]