User:Jotomicron/Sandbox

1. ~~~: ~ Jotomicron 20:19, 7 October 2007 (UTC)
2. ~~~~: ~ Jotomicron 20:19, 7 October 2007 (UTC) 20:19, 7 October 2007 (UTC)
3. ~~~~~: 20:19, 7 October 2007 (UTC)

${\displaystyle {\textrm {H}}_{2}{\textrm {PO}}_{4}^{-}}$ : dihydrogenophosphate

${\displaystyle {\textrm {HPO}}_{4}^{2-}}$ : hydrogenophosphate

${\displaystyle \left\{{\begin{matrix}{\textrm {pH}}={\textrm {7,2}}+\log {\frac {\left[{\textrm {H}}_{2}{\textrm {PO}}_{4}^{-}\right]}{\left[{\textrm {HPO}}_{4}^{2-}\right]}}\\\left[{\textrm {H}}_{2}{\textrm {PO}}_{4}^{-}\right]+\left[{\textrm {HPO}}_{4}^{2-}\right]=0.1\end{matrix}}\right.\Leftrightarrow }$

${\displaystyle {\textrm {pH}}_{\textrm {final}}={\textrm {7,2}}+\log {\frac {\left[{\textrm {HPO}}_{4}^{2-}\right]-[{\textrm {HCl}}]}{\left[{\textrm {H}}_{2}{\textrm {PO}}_{4}^{-}\right]+[{\textrm {HCl}}]}}}$

${\displaystyle {\frac {\left[{\textrm {HPO}}_{4}^{2-}\right]-[{\textrm {HCl}}]}{\left[{\textrm {H}}_{2}{\textrm {PO}}_{4}^{-}\right]+[{\textrm {HCl}}]}}}$

${\displaystyle c={\frac {n}{V}}\Leftrightarrow V={\frac {n}{c}}}$

${\displaystyle {\frac {\Delta {\textrm {pH}}}{\Delta {\textrm {T}}}}={\frac {6.8-6.9}{37-0}}=-0.0027\ {\textrm {K}}^{-1}}$

${\displaystyle {\frac {\Delta {\textrm {pH}}}{\Delta {\textrm {T}}}}={\frac {6.8-6.9}{37-0}}=-0.0027\ {\textrm {K}}^{-1}}$