Zimatlán de Álvarez
Municipality and town in Oaxaca, Mexico
From Wikipedia, the free encyclopedia
Zimatlán de Alvarez is a town and municipality in Oaxaca in south-western Mexico. The municipality covers an area of 255.16 km2. It is part of the Zimatlán District in the west of the Valles Centrales Region, and consists of four separate exclaves.
Country
Mexico
MexicoZimatlán de Alvarez | |
|---|---|
Municipality and town | |
Location of the municipality in Oaxaca | |
  Zimatlán de Alvarez Location in Mexico | |
| Coordinates: 16°52′N 96°47′W | |
| Country | Mexico |
| State | Oaxaca |
| Area | |
• Total | 255.16 km2 (98.52 sq mi) |
| Population (2005) | |
• Total | 18,370 |
| Time zone | UTC-6 (Central Standard Time) |
| • Summer (DST) | UTC-5 (Central Daylight Time) |
As of 2005, the municipality had a total population of 18,370.[1]
