Anexo:Integrales de funciones racionales artículo de lista de Wikimedia From Wikipedia, the free encyclopedia La siguiente es una lista de integrales de funciones racionales. ∫ ( c ) d x = c x + c {\displaystyle \int (c)dx=c{x}+c} ∫ ( x ) d x = x 2 2 {\displaystyle \int (x)dx={\frac {x^{2}}{2}}} ∫ ( a x k + b ) n d x = 1 a ∫ ( a x k + b ) n a d x = 1 a ( a x k + b ) n + 1 ( n + 1 ) k x ( p a r a : n ≠ − 1 ) {\displaystyle \int (ax^{k}+b)^{n}dx={\frac {1}{a}}\int (ax^{k}+b)^{n}adx={\frac {1}{a}}{\frac {(ax^{k}+b)^{n+1}}{(n+1)kx}}\qquad (\;para:\;n\neq -1\;)} ∫ ( a x + b ) n d x = 1 a ∫ ( a x + b ) n a d x = 1 a ( a x + b ) n + 1 n + 1 ( p a r a : n ≠ − 1 ) {\displaystyle \int (ax+b)^{n}dx={\frac {1}{a}}\int (ax+b)^{n}adx={\frac {1}{a}}{\frac {(ax+b)^{n+1}}{n+1}}\qquad (\;para:\;n\neq -1\;)} ∫ d x a x + b = 1 a ∫ ( a x + b ) − 1 a d x = 1 a ln | a x + b | {\displaystyle \int {\frac {dx}{ax+b}}={\frac {1}{a}}\int {(ax+b)^{-1}}adx={\frac {1}{a}}\ln \left|ax+b\right|} ∫ x ( a x + b ) n d x = a ( n + 1 ) x − b a 2 ( n + 1 ) ( n + 2 ) ( a x + b ) n + 1 ( p a r a : n ∉ { − 1 , − 2 } ) {\displaystyle \int x(ax+b)^{n}dx={\frac {a(n+1)x-b}{a^{2}(n+1)(n+2)}}(ax+b)^{n+1}\qquad (\;para:\;n\not \in \{-1,-2\}\;)} ∫ x d x a x + b = x a − b a 2 ln | a x + b | {\displaystyle \int {\frac {x\;dx}{ax+b}}={\frac {x}{a}}-{\frac {b}{a^{2}}}\ln \left|ax+b\right|} ∫ x d x ( a x + b ) 2 = b a 2 ( a x + b ) + 1 a 2 ln | a x + b | {\displaystyle \int {\frac {x\;dx}{(ax+b)^{2}}}={\frac {b}{a^{2}(ax+b)}}+{\frac {1}{a^{2}}}\ln \left|ax+b\right|} ∫ x d x ( a x + b ) n = a ( 1 − n ) x − b a 2 ( n − 1 ) ( n − 2 ) ( a x + b ) n − 1 ( p a r a : n ∉ { 1 , 2 } ) {\displaystyle \int {\frac {x\;dx}{(ax+b)^{n}}}={\frac {a(1-n)x-b}{a^{2}(n-1)(n-2)(ax+b)^{n-1}}}\qquad (\;para:\;n\not \in \{1,2\}\;)} ∫ x 2 d x a x + b = 1 a 3 ( ( a x + b ) 2 2 − 2 b ( a x + b ) + b 2 ln | a x + b | ) {\displaystyle \int {\frac {x^{2}\;dx}{ax+b}}={\frac {1}{a^{3}}}\left({\frac {(ax+b)^{2}}{2}}-2b(ax+b)+b^{2}\ln \left|ax+b\right|\right)} ∫ x 2 d x ( a x + b ) 2 = 1 a 3 ( a x + b − 2 b ln | a x + b | − b 2 a x + b ) {\displaystyle \int {\frac {x^{2}\;dx}{(ax+b)^{2}}}={\frac {1}{a^{3}}}\left(ax+b-2b\ln \left|ax+b\right|-{\frac {b^{2}}{ax+b}}\right)} ∫ x 2 d x ( a x + b ) 3 = 1 a 3 ( ln | a x + b | + 2 b a x + b − b 2 2 ( a x + b ) 2 ) {\displaystyle \int {\frac {x^{2}\;dx}{(ax+b)^{3}}}={\frac {1}{a^{3}}}\left(\ln \left|ax+b\right|+{\frac {2b}{ax+b}}-{\frac {b^{2}}{2(ax+b)^{2}}}\right)} ∫ x 2 d x ( a x + b ) n = 1 a 3 ( − 1 ( n − 3 ) ( a x + b ) n − 3 + 2 b ( n − 2 ) ( a + b ) n − 2 − b 2 ( n − 1 ) ( a x + b ) n − 1 ) ( p a r a : n ∉ { 1 , 2 , 3 } ) {\displaystyle \int {\frac {x^{2}\;dx}{(ax+b)^{n}}}={\frac {1}{a^{3}}}\left(-{\frac {1}{(n-3)(ax+b)^{n-3}}}+{\frac {2b}{(n-2)(a+b)^{n-2}}}-{\frac {b^{2}}{(n-1)(ax+b)^{n-1}}}\right)\qquad (\;para:\;n\not \in \{1,2,3\}\;)} ∫ d x x ( a x + b ) = − 1 b ln | a x + b x | {\displaystyle \int {\frac {dx}{x(ax+b)}}=-{\frac {1}{b}}\ln \left|{\frac {ax+b}{x}}\right|} ∫ d x x 2 ( a x + b ) = − 1 b x + a b 2 ln | a x + b x | {\displaystyle \int {\frac {dx}{x^{2}(ax+b)}}=-{\frac {1}{bx}}+{\frac {a}{b^{2}}}\ln \left|{\frac {ax+b}{x}}\right|} ∫ d x x 2 ( a x + b ) 2 = − a ( 1 b 2 ( a x + b ) + 1 a b 2 x − 2 b 3 ln | a x + b x | ) {\displaystyle \int {\frac {dx}{x^{2}(ax+b)^{2}}}=-a\left({\frac {1}{b^{2}(ax+b)}}+{\frac {1}{ab^{2}x}}-{\frac {2}{b^{3}}}\ln \left|{\frac {ax+b}{x}}\right|\right)} ∫ d x x 2 + a 2 = 1 a arctan x a {\displaystyle \int {\frac {dx}{x^{2}+a^{2}}}={\frac {1}{a}}\arctan {\frac {x}{a}}} ∫ d x x 2 − a 2 = − 1 a a r t a n h x a = 1 2 a ln a − x a + x ( p a r a : | x | < | a | ) {\displaystyle \int {\frac {dx}{x^{2}-a^{2}}}=-{\frac {1}{a}}\,\mathrm {artanh} {\frac {x}{a}}={\frac {1}{2a}}\ln {\frac {a-x}{a+x}}\qquad (\;para:\;|x|<|a|\;)} ∫ d x x 2 − a 2 = − 1 a a r c o t h x a = 1 2 a ln x − a x + a ( p a r a : | x | > | a | ) {\displaystyle \int {\frac {dx}{x^{2}-a^{2}}}=-{\frac {1}{a}}\,\mathrm {arcoth} {\frac {x}{a}}={\frac {1}{2a}}\ln {\frac {x-a}{x+a}}\qquad (\;para:\;|x|>|a|\;)} ∫ d x a x 2 + b x + c = 2 4 a c − b 2 arctan 2 a x + b 4 a c − b 2 ( p a r a : 4 a c − b 2 > 0 ) {\displaystyle \int {\frac {dx}{ax^{2}+bx+c}}={\frac {2}{\sqrt {4ac-b^{2}}}}\arctan {\frac {2ax+b}{\sqrt {4ac-b^{2}}}}\qquad (\;para:\;4ac-b^{2}>0\;)} ∫ d x a x 2 + b x + c = 2 b 2 − 4 a c a r t a n h 2 a x + b b 2 − 4 a c = 1 b 2 − 4 a c ln | 2 a x + b − b 2 − 4 a c 2 a x + b + b 2 − 4 a c | ( p a r a : 4 a c − b 2 < 0 ) {\displaystyle \int {\frac {dx}{ax^{2}+bx+c}}={\frac {2}{\sqrt {b^{2}-4ac}}}\,\mathrm {artanh} {\frac {2ax+b}{\sqrt {b^{2}-4ac}}}={\frac {1}{\sqrt {b^{2}-4ac}}}\ln \left|{\frac {2ax+b-{\sqrt {b^{2}-4ac}}}{2ax+b+{\sqrt {b^{2}-4ac}}}}\right|\qquad (\;para:\;4ac-b^{2}<0\;)} ∫ x d x a x 2 + b x + c = 1 2 a ln | a x 2 + b x + c | − b 2 a ∫ d x a x 2 + b x + c {\displaystyle \int {\frac {x\;dx}{ax^{2}+bx+c}}={\frac {1}{2a}}\ln \left|ax^{2}+bx+c\right|-{\frac {b}{2a}}\int {\frac {dx}{ax^{2}+bx+c}}} ∫ m x + n a x 2 + b x + c d x = m 2 a ln | a x 2 + b x + c | + 2 a n − b m a 4 a c − b 2 arctan 2 a x + b 4 a c − b 2 ( p a r a : 4 a c − b 2 > 0 ) {\displaystyle \int {\frac {mx+n}{ax^{2}+bx+c}}dx={\frac {m}{2a}}\ln \left|ax^{2}+bx+c\right|+{\frac {2an-bm}{a{\sqrt {4ac-b^{2}}}}}\arctan {\frac {2ax+b}{\sqrt {4ac-b^{2}}}}\qquad (\;para:\;4ac-b^{2}>0\;)} ∫ m x + n a x 2 + b x + c d x = m 2 a ln | a x 2 + b x + c | + 2 a n − b m a b 2 − 4 a c a r t a n h 2 a x + b b 2 − 4 a c ( p a r a : 4 a c − b 2 < 0 ) {\displaystyle \int {\frac {mx+n}{ax^{2}+bx+c}}dx={\frac {m}{2a}}\ln \left|ax^{2}+bx+c\right|+{\frac {2an-bm}{a{\sqrt {b^{2}-4ac}}}}\,\mathrm {artanh} {\frac {2ax+b}{\sqrt {b^{2}-4ac}}}\qquad (\;para:\;4ac-b^{2}<0\;)} ∫ d x ( a x 2 + b x + c ) n = 2 a x + b ( n − 1 ) ( 4 a c − b 2 ) ( a x 2 + b x + c ) n − 1 + ( 2 n − 3 ) 2 a ( n − 1 ) ( 4 a c − b 2 ) ∫ d x ( a x 2 + b x + c ) n − 1 {\displaystyle \int {\frac {dx}{(ax^{2}+bx+c)^{n}}}={\frac {2ax+b}{(n-1)(4ac-b^{2})(ax^{2}+bx+c)^{n-1}}}+{\frac {(2n-3)2a}{(n-1)(4ac-b^{2})}}\int {\frac {dx}{(ax^{2}+bx+c)^{n-1}}}} ∫ x d x ( a x 2 + b x + c ) n = b x + 2 c ( n − 1 ) ( 4 a c − b 2 ) ( a x 2 + b x + c ) n − 1 − b ( 2 n − 3 ) ( n − 1 ) ( 4 a c − b 2 ) ∫ d x ( a x 2 + b x + c ) n − 1 {\displaystyle \int {\frac {x\;dx}{(ax^{2}+bx+c)^{n}}}={\frac {bx+2c}{(n-1)(4ac-b^{2})(ax^{2}+bx+c)^{n-1}}}-{\frac {b(2n-3)}{(n-1)(4ac-b^{2})}}\int {\frac {dx}{(ax^{2}+bx+c)^{n-1}}}} ∫ d x x ( a x 2 + b x + c ) = 1 2 c ln | x 2 a x 2 + b x + c | − b 2 c ∫ d x a x 2 + b x + c {\displaystyle \int {\frac {dx}{x(ax^{2}+bx+c)}}={\frac {1}{2c}}\ln \left|{\frac {x^{2}}{ax^{2}+bx+c}}\right|-{\frac {b}{2c}}\int {\frac {dx}{ax^{2}+bx+c}}} Datos: Q484623 Related Articles~TimelinesTop QsFact Checks
