1792 United States presidential election in Delaware

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A presidential election was held in Delaware between November 2 and December 5, 1792, as part of the 1792 United States presidential election. The state legislature chose three members of the Electoral College, each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.

Quick facts Nominee, Party ...
1792 United States presidential election in Delaware

← 1788–89
November 2 – December 5, 1792
1796 â†’
 
Nominee George Washington John Adams
Party Independent Federalist
Home state Virginia Massachusetts
Electoral vote 3 3
Percentage 100.00% –

President before election

George Washington
Independent

Elected President

George Washington
Independent

Close

Delaware's three electors each cast one vote for the incumbent, George Washington, and one vote for John Adams, the incumbent Vice President.[1]

Results

More information Party, Candidate ...
1792 United States presidential election in Delaware[2]
Party Candidate Electoral Vote %
Independent George Washington 3 100.00%
Total votes 3 100.00%
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Results by elector

More information Party, Candidate ...
1792 United States presidential election in Delaware[2]
Party Candidate Votes %
Federalist James Sykes 26 43.33%
Federalist Gunning Bedford Sr. 17 28.33%
Federalist William Hill Wells 17 28.33%
Federalist Nathaniel Mitchell 0 0.00%
Democratic-Republican Thomas Montgomery[a] 0 0.00%
Total votes 60 100.00%
Close

See also

Notes

  1. Explicitly ran as an anti-federalist in 1792 run for governor.[3]

References

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