1792 United States presidential election in Georgia

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A presidential election was held in Georgia between November 2 and December 5, 1792, as part of the 1792 United States presidential election. The state legislature chose four representatives, or electors to the Electoral College, who voted for President and Vice President. Georgia had lost one elector compared to the previous election in 1788–89.[1]

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1792 United States presidential election in Georgia

← 1788–89
November 2 – December 5, 1792
1796 â†’
 
Nominee George Washington George Clinton
Party Independent Democratic-Republican
Home state Virginia New York
Electoral vote 4 4
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Georgia cast four electoral votes for the Independent candidate and incumbent President George Washington, as he ran effectively unopposed. The electoral votes for Vice president were cast for Democratic-Republican George Clinton from New York. These electors were elected by the Georgia General Assembly, the state legislature, rather than by popular vote.[2]

Results

More information Party, Candidate ...
1792 United States presidential election in Georgia[3]
Party Candidate Electoral vote %
Independent George Washington 4 100.00%
Total votes 4 100.00%
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Results by elector

More information Party, Candidate ...
1792 United States presidential election in Georgia[3]
Party Candidate Vice presidential vote
Democratic-Republican Benjamin Taliaferro George Clinton
Democratic-Republican John King George Clinton
Democratic-Republican Seaborn Jones George Clinton
Democratic-Republican William Gibbons George Clinton
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See also

References

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