1792 United States presidential election in Kentucky
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A presidential election was held in Kentucky between November 2 and December 5, 1792, as part of the 1792 United States presidential election. The voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President. It was the first presidential election Kentucky participated in since being admitted to the Union on June 1, 1792.[1]
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November 2 â December 5, 1792
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Kentucky cast four electoral votes for the Independent candidate and incumbent President George Washington, as he ran effectively unopposed. The electoral votes for Vice president were cast for Democratic-Republican Thomas Jefferson from Virginia, the only state to do so. The state was divided into four electoral districts with one elector each, whereupon each district's voters chose the electors.[2]
Results
| Party | Candidate | Electoral vote | % | |
|---|---|---|---|---|
| Independent | George Washington | 4 | 100.00% | |
| Total votes | 4 | 100.00% | ||
Results by elector
| Party | Candidate | Vice presidential vote | |
|---|---|---|---|
| Democratic-Republican | Benjamin Logan | Thomas Jefferson | |
| Democratic-Republican | Charles Scott | Thomas Jefferson | |
| Democratic-Republican | Notley Conn | Thomas Jefferson | |
| Democratic-Republican | Richard C. Anderson Sr. | Thomas Jefferson | |