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1796 United States presidential election in Rhode Island
From Wikipedia, the free encyclopedia
A presidential election was held in Rhode Island between November 4 to December 7, 1796, as part of the 1796 United States presidential election. Voters chose four representatives, or electors to the Electoral College who voted for president and vice president.
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November 4 â December 7, 1796
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During this election, Rhode Island cast its four electoral votes for John Adams.[1]
Results
| 1796 United States presidential election in Rhode Island[2][3]:â6â8â | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Federalist | John Adams | â | â | 4 | |
| Totals | â | â | 4 | ||
