1806 United States House of Representatives election in Delaware

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The 1806 United States House of Representatives election in Delaware was held on October 7, 1806, to elect the U.S. representative from Delaware's at-large congressional district. Incumbent Federalist James M. Broom faced re-election to a full term after winning the previous year's special election. He was challenged by three Democratic-Republicans.

Quick facts Candidate, Party ...
1806 United States House of Representatives election in Delaware

October 7, 1806 (1806-10-07)
 
Candidate James M. Broom Thomas Fitzgerald
Party Federalist Democratic-Republican
Popular vote 2,353 830
Percentage 60.52% 21.35%

 
Candidate Joseph Haslet Thomas Montgomery
Party Democratic-Republican Democratic-Republican
Popular vote 382 323
Percentage 9.83% 8.31%

U.S. representative before election

James M. Broom
Federalist

Elected U.S. representative

James M. Broom
Federalist

Close

Broom was re-elected with over 60% of the vote, with neither opponent coming close to unseating him.

Results

More information Party, Candidate ...
1806 United States House of Representatives election in Delaware[1]
Party Candidate Votes %
Federalist James M. Broom (incumbent) 2,353 60.52
Democratic-Republican Thomas Fitzgerald 830 21.35
Democratic-Republican Joseph Haslet 382 9.83
Democratic-Republican Thomas Montgomery 323 8.31
Majority 1,523 39.17
Total votes 3,888 100.00
Federalist hold
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Results by county

More information County, Broom# ...
CountyBroom#Broom%Fitzgerald#Fitzgerald%Haslet#Haslet%Montgomery#Montgomery%Total
Kent70995.94%304.06%739
New Castle92843.36%83038.79%38217.85%2,140
Sussex71971.05%29328.95%1,012
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See also

References

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