1806 Vermont gubernatorial election
From Wikipedia, the free encyclopedia
The 1806 Vermont gubernatorial election took place on September 2, 1806.[1] It resulted in the re-election of Isaac Tichenor to a one-year term.[2]
September 2, 1806
| |||||||||||||||||
| |||||||||||||||||
| |||||||||||||||||
The Vermont General Assembly met in Middlebury on October 9.[2] The Vermont House of Representatives appointed a committee to examine the votes of the freemen of Vermont for governor, lieutenant governor, treasurer, and members of the governor's council.[2]
The committee's examination of the votes showed that Governor Isaac Tichenor was chosen for a tenth one-year term.[2] In the election for lieutenant governor, the voters selected Paul Brigham for an eleventh one-year term.[2] Benjamin Swan was elected to his seventh one-year term as treasurer.[2]
In the races for lieutenant governor and treasurer, the vote totals and names of other candidates were not recorded.[2] According to a contemporary newspaper report, the vote totals for governor were as follows.[3]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Federalist | Isaac Tichenor (incumbent) | 8,351 | 53.5% | |
| Democratic-Republican | Jonathan Robinson | 6,930 | 44.4% | |
| Write-in | 320 | 2.1% | ||
| Total votes | 15,601 | 100% | ||
