1808 United States presidential election in Kentucky
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The 1808 United States presidential election in Kentucky took place between November 4 and December 7, 1808, as part of the 1808 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.[1]
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November 4 â December 7, 1808
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Kentucky cast seven electoral votes, as one elector didn't vote, for the Democratic-Republican candidate James Madison over the Federalist candidate Charles Cotesworth Pinckney. The electoral votes for Vice President were cast for Madison's running mate George Clinton from New York. The state was divided into two electoral districts with four electors each, whereupon each district's voters chose the electors.[2]
Results
| 1808 United States presidential election in Kentucky[3] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | James Madison | 2,679 | 98.02% | 7 | |
| Federalist | Charles Cotesworth Pinckney | 54 | 1.98% | 0 | |
| None | Not Cast | â | â | 1 | |
| Totals | 2,733 | 100.0% | 8 | ||