1817 Georgia gubernatorial election
From Wikipedia, the free encyclopedia
The 1817 Georgia gubernatorial election was held on November 10, 1817, in order to elect the Governor of Georgia. Democratic-Republican candidate and incumbent acting Governor William Rabun defeated fellow Democratic-Republican candidate John Clark in a Georgia General Assembly vote.[1]
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November 10, 1817
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General election
On election day, November 10, 1817, Democratic-Republican candidate William Rabun won the election against his opponent fellow Democratic-Republican candidate John Clark. Rabun was officially sworn in as the 29th Governor of Georgia on November 10, 1817.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | William Rabun | 62 | 52.10 | |
| Democratic-Republican | John Clark | 57 | 47.90 | |
| Total votes | 119 | 100.00 | ||
| Democratic-Republican hold | ||||