1819 Delaware gubernatorial election

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The 1819 Delaware gubernatorial election was held on October 5, 1819. Incumbent Federalist Governor John Clark was unable to seek re-election due to term limits. State Senator Henry Molleston ran as Clark's successor, winning the Federalist nomination. He faced Manaen Bull, Clark's 1816 opponent, and the Democratic-Republican nominee. Molleston won by a fairly wide margin, but died on November 11, 1819, prior to assuming office. State Senate President Jacob Stout became Governor and a special election was held in 1820.[1]

Quick facts Nominee, Party ...
1819 Delaware gubernatorial election

← 1816
October 5, 1819
 
Nominee Henry Molleston Manaen Bull
Party Federalist Democratic-Republican
Popular vote 3,823 3,185
Percentage 54.55% 45.45%

Molleston:      50–60%      60–70%
Bull:      60–70%

Governor before election

John Clark
Federalist

Elected Governor

Henry Molleston †
Federalist

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General election

Results

More information Party, Candidate ...
1819 Delaware gubernatorial election[2]
Party Candidate Votes % ±%
Federalist Henry Molleston 3,823 54.55% +1.29%
Democratic-Republican Manaen Bull 3,185 45.45% −1.29%
Majority 638 9.10% +2.58%
Turnout 7,008 100.00%
Federalist hold
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References

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