1822 Rhode Island gubernatorial election
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The 1822 Rhode Island gubernatorial election was an uncontested election held on April 17, 1822, to elect the governor of Rhode Island. William C. Gibbs, the Democratic-Republican nominee, was the only candidate and so won with 100% of the vote.
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April 17, 1822[1]
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County results Gibbs: 90â100% | |||||||||||||||||
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General election
Candidates
- William C. Gibbs, Governor since 1821.[2]
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Democratic-Republican | William C. Gibbs (incumbent) | 2,092 | 100% | ||
| Majority | 2,092 | 100% | |||
| Democratic-Republican hold | Swing | ||||
County results
| County[3] | William Gibbs
Democratic-Republican |
Total votes | |
|---|---|---|---|
| # | % | ||
| Bristol | 141 | 100% | 141 |
| Kent | 349 | 100% | 349 |
| Newport | 514 | 100% | 514 |
| Providence | 755 | 100% | 755 |
| Washington | 333 | 100% | 333 |
| Totals | 2,092 | 100% | 2,092 |
