1824 Maryland gubernatorial election
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The 1824 Maryland gubernatorial election was held on December 13, 1824, in order to elect the governor of Maryland. Incumbent Democratic-Republican governor Samuel Stevens Jr. was re-elected by the Maryland General Assembly against former Federalist governor Charles Goldsborough, Democratic-Republican candidate Roger B. Taney and Federalist candidates Robert Henry Goldsborough and John Eager Howard.[1]
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December 13, 1824
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General election
On election day, December 13, 1824, incumbent Democratic-Republican governor Samuel Stevens Jr. was re-elected by the Maryland General Assembly, thereby retaining Democratic-Republican control over the office of governor. Stevens was sworn in for his third term on January 3, 1825.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | Samuel Stevens Jr. (incumbent) | 67 | 85.90 | |
| Did Not Vote | 5 | 6.41 | ||
| Federalist | Charles Goldsborough | 3 | 3.85 | |
| Democratic-Republican | Roger B. Taney | 1 | 1.28 | |
| Federalist | Robert Henry Goldsborough | 1 | 1.28 | |
| Federalist | John Eager Howard | 1 | 1.28 | |
| Total votes | 78 | 100.00 | ||
| Democratic-Republican hold | ||||