1824 United States presidential election in Virginia

The 1824 United States presidential election in Virginia took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose 24 representatives, or electors to the Electoral College, who voted for President and Vice President.

Quick facts Nominee, Party ...

1824 United States presidential election in Virginia

← 1820 October 26 – December 2, 1824 1828 â†’

Nominee William H. Crawford John Quincy Adams Andrew Jackson Party Democratic-Republican Democratic-Republican Democratic-Republican Home state Georgia Massachusetts Tennessee Running mate Nathaniel Macon John C. Calhoun John C. Calhoun Electoral vote 24 0 0 Popular vote 8,558 3,419 2,975 Percentage 55.68% 22.24% 19.35%

County Results Crawford   30–40%   40–50%   50–60%   60–70%   70–80%   80–90%   90–100% Adams   30–40%   40–50%   50–60%   60–70%   70–80% Jackson   40–50%   50–60%   60–70%   70–80% Clay   30–40%   80–90% Tie   40–50% No Data/Vote

President before election James Monroe Democratic-Republican Elected President John Quincy Adams Democratic-Republican

Close

During this election, the Democratic-Republican Party was the only major national party, and 4 candidates from this party sought the Presidency. Virginia voted for William H. Crawford over John Quincy Adams, Andrew Jackson, and Henry Clay. Crawford won Virginia by a margin of 33.44%. This was the first presidential election that four candidates each won at least one county in the same state. This feat would be shared by Illinois in the same election; however, the only other occurrences in presidential election history have been in 1860 (in Missouri), and in 1912 (in North Dakota and in Kansas).^[1]