1826 Delaware gubernatorial election
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The 1826 Delaware gubernatorial election was held on October 3, 1826. Incumbent Federalist Governor Samuel Paynter was barred from seeking re-election to a second consecutive term. State Senator Charles Polk Jr. ran as the Federalist nominee to succeed Paynter, while 1823 Democratic-Republican nominee David Hazzard once again ran as his party's nominee. Polk defeated Hazzard by a narrow margin, barely holding onto the governorship for the Federalists.[1]
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October 3, 1826
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 Polk: 60â70% Hazzard: 50â60% 60â70% | |||||||||||||||||
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General election
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Federalist | Charles Polk Jr. | 4,333 | 50.55% | â1.21% | |
| Democratic-Republican | David Hazzard | 4,238 | 49.45% | +1.21% | |
| Majority | 95 | 1.11% | â2.43% | ||
| Turnout | 8,571 | 100.00% | |||
| Federalist hold | |||||