1826 New Hampshire gubernatorial election
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The 1826 New Hampshire gubernatorial election was held on March 14, 1826, in order to elect the governor of New Hampshire. Incumbent Democratic-Republican governor David L. Morril defeated former Democratic-Republican member of the New Hampshire House of Representatives Benjamin Pierce.[1]
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March 14, 1826
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 County results Morril: 50â60% 60â70% 70â80% Pierce: 50â60% 60â70% | |||||||||||||||||
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General election
On election day, March 14, 1826, incumbent Democratic-Republican governor David L. Morril won re-election by a margin of 5,291 votes against his opponent Democratic-Republican candidate Benjamin Pierce, thereby retaining Democratic-Republican control over the office of governor. Morril was sworn in for his third term on June 7, 1826.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | David L. Morril (incumbent) | 17,578 | 58.08 | |
| Democratic-Republican | Benjamin Pierce | 12,287 | 40.59 | |
| Scattering | 403 | 1.33 | ||
| Total votes | 30,268 | 100.00 | ||
| Democratic-Republican hold | ||||