1826 Vermont gubernatorial election

From Wikipedia, the free encyclopedia

The 1826 Vermont gubernatorial election took place on September 5, 1826.[1] It resulted in the election of Ezra Butler to a one-year term as governor.[2]

Quick facts Nominee, Party ...
1826 Vermont gubernatorial election

← 1825
September 5, 1826 (1826-09-05)
1827 â†’
 
Nominee Ezra Butler Joel Doolittle
Party Adams Jacksonian
Popular vote 8,966 3,157
Percentage 63.3% 22.3%

County results
Butler:      50–60%      60–70%      70–80%      80–90%      90–100%
Doolittle:      40–50%      50–60%

Governor before election

Cornelius P. Van Ness
Democratic-Republican

Elected Governor

Ezra Butler
Adams

Close

The Vermont General Assembly met in Montpelier on October 12.[2] The Vermont House of Representatives appointed a committee to review the votes of the freemen of Vermont for governor, lieutenant governor, treasurer, and members of the governor's council.[2] The committee determined that Ezra Butler had won a one-year term.[2]

In the election for lieutenant governor, the committee determined that Democratic-Republican Aaron Leland had won election to a fifth one-year term.[2] Newspapers of the time reported the vote totals as: Leland, 7,749 (61.9%); Henry Olin, 4,331 (34.7%); Scattering, 431 (3.4%).[3]

Benjamin Swan had no opposition for election to a one-year term as treasurer, his twenty-seventh.[2] Though he had nominally been a Federalist, Swan was usually endorsed by the Democratic-Republicans and even after the demise of the Federalist Party he was frequently unopposed.[4]

The vote totals in the governor's race were reported as follows:[2]

Results

More information Party, Candidate ...
1826 Vermont gubernatorial election[5]
Party Candidate Votes %
Adams Ezra Butler 8,966 63.3%
Jacksonian Joel Doolittle 3,157 22.3%
Write-in 2,037 14.4%
Total votes 14,160 100%
Close

References

Related Articles

Wikiwand AI