1826 Vermont gubernatorial election
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The 1826 Vermont gubernatorial election took place on September 5, 1826.[1] It resulted in the election of Ezra Butler to a one-year term as governor.[2]
September 5, 1826
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County results Butler: 50â60% 60â70% 70â80% 80â90% 90â100% Doolittle: 40â50% 50â60% | |||||||||||||||||
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The Vermont General Assembly met in Montpelier on October 12.[2] The Vermont House of Representatives appointed a committee to review the votes of the freemen of Vermont for governor, lieutenant governor, treasurer, and members of the governor's council.[2] The committee determined that Ezra Butler had won a one-year term.[2]
In the election for lieutenant governor, the committee determined that Democratic-Republican Aaron Leland had won election to a fifth one-year term.[2] Newspapers of the time reported the vote totals as: Leland, 7,749 (61.9%); Henry Olin, 4,331 (34.7%); Scattering, 431 (3.4%).[3]
Benjamin Swan had no opposition for election to a one-year term as treasurer, his twenty-seventh.[2] Though he had nominally been a Federalist, Swan was usually endorsed by the Democratic-Republicans and even after the demise of the Federalist Party he was frequently unopposed.[4]
The vote totals in the governor's race were reported as follows:[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Adams | Ezra Butler | 8,966 | 63.3% | |
| Jacksonian | Joel Doolittle | 3,157 | 22.3% | |
| Write-in | 2,037 | 14.4% | ||
| Total votes | 14,160 | 100% | ||