1827 Tennessee gubernatorial election
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The 1827 Tennessee gubernatorial election was held between August 2 and 3, 1827 in order to elect the governor of Tennessee. Democratic candidate and former Jacksonian member of the U.S. House of Representatives from Tennessee's 7th district Sam Houston defeated Democratic-Republican candidate and former member of the U.S. House of Representatives from Tennessee's 5th district Newton Cannon and former Democratic-Republican governor Willie Blount.[1]
August 2â3, 1827
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 County results Houston: 40â50% 50â60% 60â70% 70â80% 80â90% >90% Cannon 50â60% 60â70% 70â80% >90% Blount 40â50% | |||||||||||||||||||||
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General election
On election day, August 2, 1827, Democratic candidate Sam Houston won the election by a margin of 11,314 votes against his foremost opponent and fellow Democratic-Republican candidate Newton Cannon, thereby gaining Democratic control over the office of governor. Houston was sworn in as the 6th governor of Tennessee on October 1, 1827.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Sam Houston | 44,243 | 56.04% | |
| Democratic-Republican | Newton Cannon | 32,929 | 41.71% | |
| Democratic-Republican | Willie Blount | 1,784 | 2.25% | |
| Total votes | 78,956 | 100.00 | ||
| Democratic gain from Democratic-Republican | ||||