1832 United States presidential election in Delaware

The 1832 United States presidential election in Delaware took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

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1832 United States presidential election in Delaware

← 1828 November 2 – December 5, 1832 1836 â†’

Nominee Henry Clay Andrew Jackson Party National Republican Democratic Home state Kentucky Tennessee Running mate John Sergeant Martin Van Buren Electoral vote 3 0 Popular vote 4,276 4,105 Percentage 51.02% 48.98%

County results Clay   50–60% Jackson   50–60%

President before election Andrew Jackson Democratic Elected President Andrew Jackson Democratic

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Delaware voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson. Clay won the state by a narrow margin of 2.04%. This was the first election in which Delaware voted by popular vote for president in a contested election. It had used the congressional district method in the uncontested election of 1788–89, but had since changed to selecting its electors through the state legislature from 1792 to 1828.^[1]