1832 United States presidential election in Rhode Island

The 1832 United States presidential election in Rhode Island took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

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1832 United States presidential election in Rhode Island

← 1828 November 2 – December 5, 1832 1836 â†’

Nominee Henry Clay Andrew Jackson Party National Republican Democratic Home state Kentucky Tennessee Running mate John Sergeant Martin Van Buren Electoral vote 4 0 Popular vote 2,810 2,126 Percentage 56.93% 43.07%

County Results Clay   40–50%   50–60% Jackson   50–60%

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Rhode Island voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson. Clay won Rhode Island by a margin of 13.86%.

Jackson remains the only Democrat to win two consecutive terms without carrying Rhode Island either time.