1836 New Hampshire gubernatorial election

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The 1836 New Hampshire gubernatorial election was held on March 8, 1836, to elect the Governor of New Hampshire. The Democratic former U.S. senator from New Hampshire Isaac Hill defeated the Whig candidate Joseph Healey and the Federalist former Attorney General of New Hampshire George Sullivan.[1]

Quick facts Nominee, Party ...
1836 New Hampshire gubernatorial election

← 1835
March 8, 1836
1837 â†’
 
Nominee Isaac Hill Joseph Healey George Sullivan
Party Democratic Whig Federalist
Popular vote 24,904 2,566 2,230
Percentage 81.22% 8.37% 7.27%

County results
Hill:      50–60%      60–70%      80–90%      90–100%

Governor before election

William Badger
Democratic

Elected Governor

Isaac Hill
Democratic

Close

Hill's re-election was considered nearly inevitable, and his opponents struggled to recruit a candidate to contest the election. In March, the Democratic Rhode Island Republican reported that the defunct Federalist Party had nominated Sullivan, but he had declined to run.[2]

General election

Results

More information Party, Candidate ...
New Hampshire gubernatorial election, 1836
Party Candidate Votes %
Democratic Isaac Hill 24,904 81.22
Whig Joseph Healey 2,566 8.37
Federalist George Sullivan 2,230 7.27
Scattering 961 3.14
Total votes 30,661 100.00
Democratic hold
Close

References

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