1836 New Hampshire gubernatorial election
From Wikipedia, the free encyclopedia
The 1836 New Hampshire gubernatorial election was held on March 8, 1836, to elect the Governor of New Hampshire. The Democratic former U.S. senator from New Hampshire Isaac Hill defeated the Whig candidate Joseph Healey and the Federalist former Attorney General of New Hampshire George Sullivan.[1]
March 8, 1836
| |||||||||||||||||||||
| |||||||||||||||||||||
County results Hill: 50â60% 60â70% 80â90% 90â100% | |||||||||||||||||||||
| |||||||||||||||||||||
Hill's re-election was considered nearly inevitable, and his opponents struggled to recruit a candidate to contest the election. In March, the Democratic Rhode Island Republican reported that the defunct Federalist Party had nominated Sullivan, but he had declined to run.[2]
General election
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Isaac Hill | 24,904 | 81.22 | |
| Whig | Joseph Healey | 2,566 | 8.37 | |
| Federalist | George Sullivan | 2,230 | 7.27 | |
| Scattering | 961 | 3.14 | ||
| Total votes | 30,661 | 100.00 | ||
| Democratic hold | ||||