1836 Rhode Island gubernatorial election
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The 1836 Rhode Island gubernatorial election was held on April 20, 1836.[1]
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April 20, 1836
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 County results Francis: 50â60% 60â70% | |||||||||||||||||
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Incumbent Democratic governor John Brown Francis won re-election to a fourth term, defeating Whig nominee Tristam Burges and Constitutional Party candidate Charles Collins.
General election
Candidates
- John Brown Francis, Democratic, incumbent governor
- Tristam Burges, Whig, former U.S. representative
- Charles Collins, of Middletown, Constitutional[2][3][4]
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Democratic | John Brown Francis (incumbent) | 4,020 | 56.22% | ||
| Whig | Tristam Burges | 2,984 | 41.73% | ||
| Constitutional Party | Charles Collins | 135 | 1.89% | ||
| Scattering | 12 | 0.17% | |||
| Majority | 1,036 | 14.49% | |||
| Turnout | 7,151 | ||||
| Democratic hold | Swing | ||||