1836 United States presidential election in Kentucky

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The 1836 United States presidential election in Kentucky was held between November 7 and 9, 1836 as part of the 1836 United States presidential election.[1] Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

Quick facts Nominee, Party ...
1836 United States presidential election in Kentucky
← 1832
November 7–9, 1836
1840 â†’
← MI
NY â†’
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate Francis Granger Richard Mentor Johnson
Electoral vote 15 0
Popular vote 36,861 33,229
Percentage 52.59% 47.41%

County Results
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Kentucky voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Kentucky by a margin of 5.18%.

Results

More information Party, Candidate ...
1836 United States presidential election in Kentucky[2]
Party Candidate Votes Percentage Electoral votes
Whig William Henry Harrison 36,861 52.59% 15
Democratic Martin Van Buren 33,229 47.41% 0
Totals 70,090 100.0% 15
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References

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