1836 United States presidential election in Virginia
From Wikipedia, the free encyclopedia
A presidential election was held in Virginia on November 7, 1836 as part of the 1836 United States presidential election.[1] Voters chose 23 representatives, or electors to the Electoral College, who voted for President and Vice President.
November 7, 1836
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
County results
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
Virginia voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh Lawson White. Van Buren won Virginia by a margin of 13.29%. While Van Buren's national running mate was Richard Mentor Johnson, the Virginia Democratic electors refused to support his candidacy and voted for William Smith of South Carolina.
Results
| 1836 United States presidential election in Virginia[2] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Martin Van Buren | 30,556 | 56.64% | 23 | |
| Whig | Hugh Lawson White | 23,384 | 43.35% | 0 | |
| N/A | Others | 5 | 0.01% | 0 | |
| Totals | 53,945 | 100.00% | 23 | ||
