1838 Rhode Island gubernatorial election
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The 1838 Rhode Island gubernatorial election was held on April 18, 1838.[1][2]
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April 18, 1838
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 County results Sprague: 50â60% 60â70% Francis: 50â60% | |||||||||||||||||
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Incumbent Democratic governor John Brown Francis ran for election to a sixth term but was defeated by Whig nominee William Sprague.
General election
Candidates
- John Brown Francis, Democratic, incumbent governor
- William Sprague, Whig, former U.S. representative
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Whig | William Sprague | 3,984 | 52.51% | ||
| Democratic | John Brown Francis (incumbent) | 3,504 | 46.18% | ||
| Scattering | 99 | 1.30% | |||
| Majority | 480 | 6.33% | |||
| Turnout | 7,587 | ||||
| Whig gain from Democratic | Swing | ||||