1840 Indiana gubernatorial election

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The 1840 Indiana gubernatorial election was held on August 3, 1840, in order to elect the Governor of Indiana. Whig nominee and former member of the Indiana House of Representatives Samuel Bigger defeated Democratic nominee and incumbent member of the U.S. House of Representatives from Indiana's 7th district Tilghman Howard.[1]

Quick facts Nominee, Party ...
1840 Indiana gubernatorial election

← 1837
August 3, 1840
1843 â†’
 
Nominee Samuel Bigger Tilghman Howard
Party Whig Democratic
Popular vote 62,932 54,274
Percentage 53.69% 46.31%

County results
Bigger:      50–60%      60–70%
Howard:      50–60%      60–70%      70–80%      80–90%
No Vote/Data:      

Governor before election

David Wallace
Whig

Elected Governor

Samuel Bigger
Whig

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General election

On election day, August 3, 1840, Whig nominee Samuel Bigger won the election by a margin of 8,658 votes against his opponent Democratic nominee Tilghman Howard, thereby retaining Whig control over the office of Governor. Bigger was sworn in as the 7th Governor of Indiana on December 9, 1840.[2]

Results

More information Party, Candidate ...
Indiana gubernatorial election, 1840[3]
Party Candidate Votes %
Whig Samuel Bigger 62,932 53.69
Democratic Tilghman Howard 54,274 46.31
Total votes 117,206 100.00
Whig hold
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References

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