1840 United States presidential election in Arkansas

A presidential election was held in Arkansas on November 2, 1840 as part of the 1840 United States presidential election.^[1] Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

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1840 United States presidential election in Arkansas

← 1836 November 2, 1840 1844 â†’

← PA CT â†’

Nominee Martin Van Buren William H. Harrison Party Democratic Whig Home state New York Ohio Running mate Richard Mentor Johnson John Tyler Electoral vote 3 0 Popular vote 6,679 5,160 Percentage 56.42% 43.58%

County results Van Buren   50–60%   60–70%   70–80%   80–90%   90–100% Harrison   50–60%   60–70%   70–80%   80–90% Unknown/No vote

President before election Martin Van Buren Democratic Elected President William H. Harrison Whig

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Arkansas voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Arkansas by a margin of 12.84%.