1840 United States presidential election in Delaware
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The 1840 United States presidential election in Delaware was held on November 10, 1840 as part of the 1840 United States presidential election.[1] Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.
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November 10, 1840
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 County results
Harrison 50â60%
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Delaware voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Delaware by a margin of 10.1%.
Results
| Party | Pledged to | Elector | Votes | |
|---|---|---|---|---|
| Whig Party | William Henry Harrison | Peter F. Causey | 5,967 | |
| Whig Party | William Henry Harrison | Benjamin Caulk | 5,962 | |
| Whig Party | William Henry Harrison | Henry F. Hall | 5,958 | |
| Democratic Party | Martin Van Buren | Thomas Jacobs | 4,872 | |
| Democratic Party | Martin Van Buren | Christopher Vandergrift | 4,871 | |
| Democratic Party | Martin Van Buren | Nehemiah Clarke | 4,870 | |
| Write-in | Scattering | 13 | ||
| Votes cast[a] | 10,852 | |||
Results by county
| County[2][3] | William Henry Harrison Whig |
Martin Van Buren Democratic |
Margin | Total votes cast[a] | |||
|---|---|---|---|---|---|---|---|
| # | % | # | % | # | % | ||
| Kent | 1,593 | 59.20% | 1,095 | 40.69% | 498 | 18.51% | 2,691[b] |
| New Castle | 2,321 | 51.28% | 2,195 | 48.50% | 126 | 2.78% | 4,526[c] |
| Sussex | 2,053 | 56.48% | 1,582 | 43.52% | 471 | 12.96% | 3,635 |
| Totals | 5,967 | 54.99% | 4,872 | 44.89% | 1,095 | 10.09% | 10,852 |
