1840 United States presidential election in Tennessee
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The 1840 United States presidential election in Tennessee was held on November 3, 1840 as part of the 1840 United States presidential election.[1] Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.
November 3, 1840
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County results
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Tennessee voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won the state by a margin of 11.32%.
Results
| 1840 United States presidential election in Tennessee[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Whig | William Henry Harrison of Ohio | John Tyler of Virginia | 60,194 | 55.66% | 15 | 100.00% | ||
| Democratic | Martin Van Buren of New York | Richard Mentor Johnson of Kentucky | 47,951 | 44.34% | 0 | 0.00% | ||
| Total | 108,145 | 100.00% | 15 | 100.00% | ||||