1844 Connecticut gubernatorial election

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The 1844 Connecticut gubernatorial election was held on April 1, 1844.[1][2] Former state legislator, Amistad lawyer and Whig nominee Roger Sherman Baldwin was elected, defeating incumbent governor and Democratic nominee Chauncey Fitch Cleveland with 49.41% of the vote.

Quick facts Nominee, Party ...
1844 Connecticut gubernatorial election

← 1843
April 1, 1844
1845 â†’
 
Nominee Roger Sherman Baldwin Chauncey Fitch Cleveland
Party Whig Democratic
Electoral vote 116 93
Popular vote 30,093 28,846
Percentage 49.41% 47.36%

Baldwin:      40–50%      50–60%      60–70%      70–80%
Cleveland:      40–50%      50–60%      60–70%      70–80%
Tie:      50%

Governor before election

Chauncey Fitch Cleveland
Democratic

Elected Governor

Roger Sherman Baldwin
Whig

Close

Although Baldwin won a plurality of the vote, he fell short of a majority. The state constitution at the time required that in such a case, the Connecticut General Assembly decides the election. The state legislature voted for Baldwin, 116 to 93, and Baldwin became the governor.[3]

General election

Candidates

Major party candidates

  • Roger Sherman Baldwin, Whig
  • Chauncey Fitch Cleveland, Democratic

Minor party candidates

  • Francis Gillette, Liberty

Results

More information Party, Candidate ...
1844 Connecticut gubernatorial election[4]
Party Candidate Votes % ±%
Whig Roger Sherman Baldwin 30,093 49.41%
Democratic Chauncey Fitch Cleveland (incumbent) 28,846 47.36%
Liberty Francis Gillette 1,971 3.24%
Plurality 1,247
Turnout
Close
More information Party, Candidate ...
1844 Connecticut gubernatorial election, contingent General Assembly election
Party Candidate Votes % ±%
Whig Roger Sherman Baldwin 116 55.50%
Democratic Chauncey Fitch Cleveland (incumbent) 93 44.50%
Majority 23
Whig gain from Democratic Swing
Close

References

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