1844 United States presidential election in Ohio
From Wikipedia, the free encyclopedia
A presidential election was held in Ohio on November 1, 1844 as part of the 1844 United States presidential election.[1] Voters chose 23 representatives, or electors to the Electoral College, who voted for President and Vice President.
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November 1, 1844
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Results
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Ohio voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won Ohio by a narrow margin of 1.94%. This was last election where a Whig won Ohio.
Results
| 1844 United States presidential election in Ohio[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 155,113 | 49.68% | 23 | 100.00% | ||
| Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 149,061 | 47.74% | 0 | 0.00% | ||
| Liberty | James G. Birney of Michigan | Thomas Morris of Ohio | 8,050 | 2.58% | 0 | 0.00% | ||
| Total | 312,224 | 100.00% | 23 | 100.00% | ||||
