1845 Vermont gubernatorial election
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The 1845 Vermont gubernatorial election was held on September 2, 1845.[1]
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September 2, 1845
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 County results Slade: 40â50% 50â60% 60â70% Kellogg: 40â50% 50â60% | |||||||||||||||||||||||||
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Incumbent Whig Governor William Slade defeated Democratic nominee Daniel Kellogg and Liberty nominee William R. Shafter.
Since no candidate received a majority in the popular vote, Slade was elected by the Vermont General Assembly per the state constitution.
General election
Candidates
- Daniel Kellogg, Democratic, former United States Attorney for the District of Vermont,[2] Democratic nominee for governor in 1843 and 1844
- William R. Shafter, Liberty, farmer and judge,[3] Liberty nominee for governor in 1844
- William Slade, Whig, incumbent governor
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Whig | William Slade (inc.) | 22,770 | 47.18% | ||
| Democratic | Daniel Kellogg | 18,594 | 38.53% | ||
| Liberty | William R. Shafter | 6,534 | 13.54% | ||
| Scattering | 362 | 0.75% | |||
| Majority | 4,176 | 8.65% | |||
| Turnout | 48,260 | ||||
Legislative election
As no candidate received a majority of the vote, the Vermont General Assembly was required to decide the election, both Houses meeting jointly choosing among the top three vote-getters, Slade, Kellogg, and Shafter. The legislative election was held on October 9, 1845.[12][13][14]
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Whig | William Slade | 132 | 59.73% | |
| Democratic | Daniel Kellogg | 75 | 33.94% | |
| Liberty | William R. Shafter | 14 | 6.33% | |
| Turnout | 221 | |||
| Whig hold | ||||
