1846 Indiana gubernatorial election

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The 1846 Indiana gubernatorial election was held on August 3, 1846.[1]

Quick facts Nominee, Party ...
1846 Indiana gubernatorial election

← 1843
August 3, 1846
1849 â†’
 
Nominee James Whitcomb Joseph G. Marshall
Party Democratic Whig
Popular vote 64,104 60,138
Percentage 50.65% 47.52%

County results
Whitcomb:      40–50%      50–60%      60–70%      70–80%      80–90%

Marshall:      40–50%      50–60%      60–70%

No Vote/Data:      

Governor before election

James Whitcomb
Democratic

Elected Governor

James Whitcomb
Democratic

Close

Incumbent Democratic Governor James Whitcomb defeated Whig nominee Joseph G. Marshall and Liberty nominee Stephen C. Stevens with 50.65% of the vote.

General election

Candidates

Results

More information Party, Candidate ...
1846 Indiana gubernatorial election[4][5][6][7][8][9][10][a]
Party Candidate Votes %
Democratic James Whitcomb 64,104 50.65%
Whig Joseph G. Marshall 60,138 47.52%
Liberty Stephen C. Stevens 2,301 1.82%
Write-in Joseph S. Harding 17 0.01
Write-in John Burk 2 0.00
Write-in J. C. Stephenson 1 0.00
Write-in David Wallace 1 0.00
Majority 3,966 3.13%
Turnout 126,564
Democratic hold
Close

Notes

  1. The Indiana State Senate Journal and some other sources give the result as Whitcomb 64,104, Marshall 60,067, Stevens 2,278.[11][12][13]

References

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