1846 Ohio gubernatorial election
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The 1846 Ohio gubernatorial election was held on October 13, 1846, in order to elect the Governor of Ohio. Whig nominee William Bebb defeated Democratic nominee David Tod and Liberty nominee Samuel Lewis.[1]
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October 13, 1846
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 Election results by county Bebb: 40â50% 50â60% 60â70% Tod: 40â50% 50â60% 60â70% 80â90% No Data/Vote: | |||||||||||||||||
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General election
On election day, October 13, 1846, Whig nominee William Bebb won the election by a margin of 2,385 votes against his foremost opponent Democratic nominee David Tod, thereby retaining Whig control over the office of Governor. Bebb was sworn in as the 19th Governor of Ohio on December 12, 1846.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Whig | William Bebb | 118,869 | 48.28% | |
| Democratic | David Tod | 116,484 | 47.31% | |
| Liberty | Samuel Lewis | 10,797 | 4.39% | |
| Scattering | 46 | 0.02% | ||
| Total votes | 246,196 | 100.00% | ||
| Whig hold | ||||