1846 Rhode Island gubernatorial election
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The 1846 Rhode Island gubernatorial election was held on April 1, 1846, in order to elect the governor of Rhode Island. Law and Order nominee and incumbent lieutenant governor Byron Diman defeated incumbent Liberation governor Charles Jackson, who was jointly nominated by the Democratic Party. However, as no candidate received a majority of the total votes cast as was required by Rhode Island law, the election was forwarded to the Rhode Island legislature, who chose Diman as governor.[1]
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April 1, 1846
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 County results Diman: 50â60% 60â70% 70â80% Jackson: 50â60% | ||||||||||||||||||||
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General election
On election day, April 1, 1846, Law and Order nominee Byron Diman won the election by a margin of 86 votes against his opponent incumbent Liberation governor Charles Jackson, thereby gaining Law and Order control over the office of governor. Diman was sworn in as the 19th governor of Rhode Island on May 6, 1846.
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Law and Order | Byron Diman | 7,477 | 49.77 | |
| Democratic | Charles Jackson (incumbent) | 7,391 | 49.20 | |
| Scattering | 155 | 1.03 | ||
| Total votes | 15,023 | 100.00 | ||
| Law and Order gain from Liberation | ||||