1849 Connecticut gubernatorial election

The 1849 Connecticut gubernatorial election was held on April 2, 1849.^[1] Former congressman and Whig nominee Joseph Trumbull defeated former congressman and Democratic nominee Thomas H. Seymour as well as former Senator and Free Soil nominee John M. Niles with 49.35% of the vote. Niles had previously been the Democratic nominee for this same office in 1840.

Quick facts Nominee, Party ...

1849 Connecticut gubernatorial election

← 1848 April 2, 1849 1850 â†’

Nominee Joseph Trumbull Thomas H. Seymour John M. Niles Party Whig Democratic Free Soil Electoral vote 122 110 Popular vote 27,800 25,018 3,520 Percentage 49.35% 44.41% 6.25%

County results Municipality results Trumbull:      30–40%      40–50%      50–60%      60–70%      70–80% Seymour:      30–40%      40–50%      50–60%      60–70%      70–80% Tie:      40–50%

Governor before election Clark Bissell Whig Elected Governor Joseph Trumbull Whig

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Trumbull won a plurality of the vote, but fell short of a majority. As a result, the Connecticut General Assembly elected the governor, per the state constitution. Trumbull won the vote over Seymour 122 to 110 in the General Assembly, and became the governor.^[2] This was the first of six consecutive elections in which the Free Soil Party participated.