1852 United States presidential election in Arkansas
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The 1852 United States presidential election in Arkansas took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.
November 2, 1852
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County results
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Arkansas voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Arkansas by a margin of 24.36%.
Results
| 1852 United States presidential election in Arkansas[1][2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Franklin Pierce of New Hampshire | William R. King of Alabama | 12,173 | 62.18% | 4 | 100.00% | ||
| Whig | Winfield Scott of New Jersey | William Alexander Graham of North Carolina | 7,404 | 37.82% | 0 | 0.00% | ||
| Total | 19,577 | 100.00% | 4 | 100.00% | ||||