1852 United States presidential election in Arkansas

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The 1852 United States presidential election in Arkansas took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Quick facts Nominee, Party ...
1852 United States presidential election in Arkansas

← 1848
November 2, 1852
1856 â†’
 
Nominee Franklin Pierce Winfield Scott
Party Democratic Whig
Home state New Hampshire New Jersey
Running mate William R. King William Alexander Graham
Electoral vote 4 0
Popular vote 12,173 7,404
Percentage 62.18% 37.82%

County results

President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

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Arkansas voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Arkansas by a margin of 24.36%.

Results

More information Party, Candidate ...
1852 United States presidential election in Arkansas[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Franklin Pierce of New Hampshire William R. King of Alabama 12,173 62.18% 4 100.00%
Whig Winfield Scott of New Jersey William Alexander Graham of North Carolina 7,404 37.82% 0 0.00%
Total 19,577 100.00% 4 100.00%
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See also

References

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