1852 Vermont gubernatorial election

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The 1852 Vermont gubernatorial election was held on Tuesday, September 7.[1] Incumbent governor Charles K. Williams, a Whig, was not a candidate for reelection.[2] In the voting, Whig Erastus Fairbanks received 49.2 percent, Democrat John S. Robinson 31.3 percent, and Free Soil Party nominee Lawrence Brainerd 19.6 percent.[3]

Quick facts Nominee, Party ...
1852 Vermont gubernatorial election

← 1851
September 7, 1852 (1852-09-07)
1853 â†’
 
Nominee Erastus Fairbanks John S. Robinson Lawrence Brainerd
Party Whig Democratic Free Soil
Electoral vote 117 61 40
Popular vote 23,795 14,938 9,445
Percentage 49.2% 31.3% 19.6%

County results
Fairbanks:      30–40%      40–50%      50–60%      60–70%
Robinson:      40–50%      50–60%
Brainerd:      40–50%

Governor before election

Charles K. Williams
Whig

Elected Governor

Erastus Fairbanks
Whig

Close

In accordance with the Vermont Constitution, because no candidate received 50 percent of the vote, the election was decided by the Vermont General Assembly.[3] On October 16, with 110 votes by the combined Vermont House of Representatives and Vermont Senate necessary for a choice, Fairbanks won on the first ballot with 117 votes to 61 for Robinson and 40 for Brainerd.[3] On Monday October 18, Fairbanks took the oath of office and began a one-year term.[4]

General election

Results

More information Party, Candidate ...
1852 Vermont gubernatorial election[5]
Party Candidate Votes % ±%
Whig Erastus Fairbanks 23,795 49.2%
Democratic John Robinson 14,938 31.3%
Free Soil Lawrence Brainerd 9,445 19.6%
Write-in Other 20 0.0
Total votes '48,198' '100'
Close

References

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