1856 United States presidential election in Georgia

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The 1856 United States presidential election in Georgia took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for president and vice president.

Quick facts Nominee, Party ...
1856 United States presidential election in Georgia
← 1852
November 4, 1856
1860 â†’
 
Nominee James Buchanan Millard Fillmore
Party Democratic Know Nothing
Home state Pennsylvania New York
Running mate John C. Breckinridge Andrew Jackson Donelson
Electoral vote 10 0
Popular vote 56,581 42,439
Percentage 57.14% 42.86%

County Results

President before election

Franklin Pierce
Democratic

Elected President

James Buchanan
Democratic

Close

Georgia voted for the Democratic candidate, James Buchanan, over American Party candidate Millard Fillmore. Buchanan won Georgia by a margin of 14.28%.

Republican Party candidate John C. Frémont was not on the ballot in the state, despite being born in Savannah.

Results

More information Party, Candidate ...
1856 United States presidential election in Georgia[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic James Buchanan of Pennsylvania John C. Breckinridge of Kentucky 56,581 57.14% 10 100.00%
Know Nothing Millard Fillmore of New York Andrew Jackson Donelson of Tennessee 42,439 42.86% 0 0.00%
Total 99,020 100.00% 10 100.00%
Close

See also

References

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