1860 Chicago mayoral election
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In the Chicago mayoral election of 1860, Democratic nominee John Wentworth defeated Republican nominee Walter S. Gurnee.
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March 3, 1860
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Both candidates had served as mayor before. Incidentally, each had previously been mayor under the opposite party affiliation. Gurnee had served two terms as a Democrat, having been elected in 1851 and 1852, Wentworth had previously served one term as a Republican, having been elected in 1857.
The election was held on March 3.[1]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | John Wentworth | 9,998 | 53.36 | |
| Republican | Walter S. Gurnee | 8,739 | 46.64 | |
| Turnout | 18,737 | |||
