1867 Iowa gubernatorial election
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The 1867 Iowa gubernatorial election was held on October 8, 1867. Republican nominee Samuel Merrill defeated Democratic nominee Charles Mason with 58.88% of the vote.
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October 8, 1867
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 County results Merrill: 50â60% 60â70% 70â80% 80â90% 90â100% Mason: 50â60% 60â70% No Data/Votes: | |||||||||||||||||
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General election
Candidates
- Samuel Merrill, Republican
- Charles Mason, Democratic
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Samuel Merrill | 90,204 | 58.88% | ||
| Democratic | Charles Mason | 62,966 | 41.10% | ||
| Majority | 27,238 | ||||
| Turnout | |||||
| Republican hold | Swing | ||||