1867 Minnesota Attorney General election
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The 1867 Minnesota Attorney General election was held on November 5, 1867, in order to elect the attorney general of Minnesota. Republican nominee and former member of the Minnesota House of Representatives Francis R. E. Cornell defeated Democratic nominee and former Justice of the Supreme Court of Minnesota Territory Andrew G. Chatfield.[1]
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November 5, 1867
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General election
On election day, November 5, 1867, Republican nominee Francis R. E. Cornell won the election by a margin of 5,739 votes against his opponent Democratic nominee Andrew G. Chatfield, thereby gaining Republican control over the office of attorney general. Cornell was sworn in as the 4th attorney general of Minnesota on January 8, 1868.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Francis R. E. Cornell | 34,657 | 53.84 | |
| Democratic | Andrew G. Chatfield | 28,918 | 44.92 | |
| Write-in | 801 | 1.24 | ||
| Total votes | 64,376 | 100.00 | ||
| Republican gain from National Union | ||||